Description

For this challenge, we need to reverse a briefly obfuscated python script to find an input value that will validate some conditions to get the flag.

#!/usr/bin/env python3

from binascii import unhexlify as sOup
from operator import attrgetter as souP

ME_FLAGE = 'censored'

SoUp = input
soUP = hex
sOUp = print
sOuP = ord
SOuP = open

def SoUP(sOUP):
 soup = 0
 while sOUP != 0:
  soup = (soup * 10) + (sOUP % 10)
  sOUP //= 10
 return soup

def SOup(sOUP):
 soup = 0
 for soUp in sOUP:
  soup *= 10
  soup += sOuP(soUp) - sOuP('0')
 return soup

def SOUP():
 Soup = SoUp()[:7]
 print(Soup)
 if not souP('isdigit')(Soup)():
  sOUp("that's not a number lol")
  return

 soup = SoUP(SOup(Soup))
 SouP = souP('zfill')(soUP(soup)[2:])(8)[-8:]
 if sOup(SouP) == souP('encode')('s0up')():
  sOUp("oh yay it's a flag!", ME_FLAGE)
 else:
  sOUp('oh noes rip u')

if __name__ == '__main__':
 SOUP()

Continue reading [EasyCTF 2018] [Reverse 150 – Soupstitution Cipher] Write Up →